1(6,9)2(2,5)$42(No, that's incorrect. Try again.HINT: )$43($4255You may have distributed incorrectly. Check your work.)$44($4255You didn't distribute the constant through on the right side of the equation.)
3(1e2*)20(2e3-)21(1e1-)
Solve this equation and identify its solution.1p + 3 = 1(p + 2)The solution is ? .iT12Solve this equation and identify its solution.1p + 3 = 1(p + 2)1p + 3 = 1p + 3p 3 = 3pBecause the statement 3 = 3 is c2TRUEc0 forall values of p, the equation has an c2INFINITEc0number of solutions. The solution is c2ALL REALNUMBERSc0.p
all real numbersno solutionR2021@@$43@$44
1(6,9)2(2,5)$42(No, that's incorrect. Try again.HINT: )$43($4255You may have distributed incorrectly. Check your work.)$44($4255You didn't distribute the constant through on the right side of the equation.)
3(1e2*)20(2e3+)21(1e1-)
Solve this equation and identify its solution.1x - 3 = 1(x + 2)The solution is ? .iT12Solve this equation and identify its solution.1x - 3 = 1(x + 2)1x - 3 = 1x + 3p -3 = 3pThe statement -3 = 3 is c2FALSEc0 for all valuesof x. There are c2NOc0 real numbers which make theequation true. There is c2NO SOLUTIONc0.p
no solutionall real numbersR2021@@$43@$44
1(3,4)2(10,15)3(-3,2)4(-30,-1)5(2,3) $42(No, that's incorrect. Try again.HINT: )$43($4255The variable should not be eliminated. Check your work.) n(3p<2)n(2=11)n(2=13)n(2=14)
Solve this equation and identify its solution.1r - 2(r + 3) = 4 + 5rThe solution is ? .iT12Solve this equation and identify its solution.1r - 2(r + 3) = 4 + 5r 1r - 2r - 6 = 4 + 5rp 7r - 6 = 4 + 5rp 8:3r - 6 = 4p 8:3r = 9p r = 98p r = 10pThe solution is 10.p
10all real numbersno solution@@$43@$43
1(3,4)2(4,8)3(5,8)5(4,5)6(-5,2) $42(No, that's incorrect. Try again.HINT: )$43($4255You may have distributed incorrectly. Check your work.)$44($4255You didn't distribute the constant through on the right side of the equation.) n(2=7) n(1e2+1-=0)
Solve this equation and identify its solution.1m + 2 + 3m = 4(m - 5) - 6The solution is ? .iT12Solve this equation and identify its solution.1:3m + 2 + 3m = 4(m - 5) - 61:3m + 2 + 3m = 4m - 7 - 6p 8m + 2 = 4m + 9p 2 = 9pBecause the statement 2 = 9 is c2TRUEc0 forall values of m, the equation has an c2INFINITEc0number of solutions. The solution is c2ALL REALNUMBERSc0.p
all real numbersno solutionR2021@@$43@$44
1(2,14)2(10,20)3(-3,5)4(-4,6)5(9,18) $42(No, that's incorrect. Try again.HINT: )$43($4255The variable should not be eliminated. Check your work.) n(1e3+p<2)n(1e3+=4)n(4p<2)
Solve this equation and identify its solution.1z + 2 + 3z = 4z + 5The solution is ? .iT12Solve this equation and identify its solution.1z + 2 + 3z = 4z + 5 6:3z + 2 = 4z + 5p 7z + 2 = 5p 7:3z = 8p z = 87p z = 9pThe solution is 9.p
9all real numbersno solution@@$43@$43
1(-6,9)2(-3,5)3(-6,5)4(2,3) $42(No, that's incorrect. Try again.HINT: )$43($4255You may have distributed incorrectly. Check your work.)$44($4255You didn't distribute the constant through on the right side of the equation.) n(1p<2)
Solve this equation and identify its solution.1:3(h - 2) + 3 = 4 - 5(h - 1)The solution is ? .iT1220 21 Solve this equation and identify its solution.1:3(h - 2) + 3 = 4 - 5(h - 1) 1:3h - 6 + 3 = 4 - 5h - 7p 10:3 + 3 = 4 - 7p 9:3 = 8pThe statement 9 = 8 is c2FALSEc0 for all valuesof h. There are c2NOc0 real numbers which make theequation true. There is c2NO SOLUTIONc0.p
no solutionall real numbersR2021@@$43@$44
1,2,3(2,9)10(2,5)4(2,9) $42(No, that's incorrect. Try again.HINT: )$43($4255You may have distributed incorrectly. Check your work.)$44($4255You didn't distribute the constant through on the right side of the equation.) n(1>5&2>5)n(1<5&2<5)n(3=10e4*) n(1e2*10*2-=0)
Solve this equation and identify its solution.1:3(5x - 3) = 6(2x - 4)The solution is ? .iT12Solve this equation and identify its solution.+481:3(5x - 3) = 6(2x - 4)30Use the distributive property. +4711:3x - 12 = 13x - 14p30Subtract 11x from both sides.1012:3 = 14pThe statement is c2FALSEc0 for all values of x, thusthere are c2NOc0 real numbers which make the equationtrue. There is c2NO SOLUTIONc0.p
no solutionall real numbersR2021@@$43@$44
1(2,9)10(2,5)2(2,5) $42(No, that's incorrect. Try again.HINT: )$43($4255You may have distributed incorrectly. Check your work.)$44($4255You didn't distribute the constant through on the right side of the equation.) n(1>5&2>5)n(1<5&2<5)
Solve this equation and identify its solution.1:3(3 - 10x) = 4(2 - x)The solution is ? .iT12Solve this equation and identify its solution.+481:3(3 - 10x) = 4(2 - x)30Use the distributive property. +475:3 - 4x = 5 - 4xp30Add 4x to both sides.105:3 = 5pBecause the statement 5 = 5 is c2TRUEc0 forall values of x, the equation has an c2INFINITEc0number of solutions. The solution is c2ALL REALNUMBERSc0.p